Chemistry, asked by barlagnaneswari, 4 months ago

Explain the hybridization involved in SF6 molecule.​

Answers

Answered by Anonymous
1

Answer:

To determine the hybridization of sulphur hexafluoride we will look at the orbitals involved and the bonds that are formed during the combination of sulphur and fluorine molecules. ... Further, the sp3d2 hybrid orbitals overlap with a 2p orbital of fluorine, and they form the S-F bond.

Bond Angle: 90o

Hybridization Type: sp3d2

Geometry: Octahedral

Name of the Molecule: Sulphur Hexafluoride

Explanation:

hope it helps you.....

Answered by shubhamgariya660
2

Answer:

In SF6 the central sulphur atom has the ground state configuration,3s23p4 one electron each from 3s and 3p orbitals is promoted to 3d orbitals These six orbitals get hybridised to form six sp3d2hybrid orbitalsThese six orbitals get hybridised to form six sp

3d

2hybrid orbitals. Each of these sp

3d

2hybrid orbitals overlaps with 2p orbital of fluorine to form S−F bond. Thus, SF

6

molecule has octahedral structure.

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