Question

explain " the law of conservation of momentum " with on example.
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Answer 1

$\huge\underline{Answer}$

The law of conservation of momentum states that the total momentum of any system of objects remains constant in the absence of any external force. According to the law of conservation of momentum, for a collision between two bodies.

Total momentum before collision = Total momentum after the collision.

m1u1 + m2u2 = m1v1 + m2v2

Example:-

When a shot is fired from a gun, the gun recoils. When the shot is fired, it leaves the barrel with a certain force. The outgoing shot causes a reaction on the gun. Thus an equal and opposite force acts on the gun and it recoils.

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Answer 2

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Let ,

mass = m

initial velocity = u

final velocity = v

here ,

m₁= 1500 kg

m₂=1000 kg

u₁ = 25 m/s

u₂ = 15 m/s

v₁ = 20 m/s

we have to find v₂ !!

v₂ is the velocity after collision

Here is a formula relating the values given ,

m₁u₁+m₂u₂ = m₁v₁ + m₂+v₂

m₁u₁+m₂u₂ = 1500 × 25 + 1000 ×15

= 37500 + 15000

= 52500

m₁v₁ + m₂+v₂ = 1500 × 20 + 1000 × v₂

= 30000 + 1000v₂

m₁u₁+m₂u₂ = m₁v₁ + m₂+v₂

52500 = 3000 + 1000v₂

1000v₂ = 52500 - 30000

1000 v₂ = 22500

v₂ = 22500/1000

= 22.5 m/s

Thus, velocity of car 'B' after collision is 22.5m/s.