Question

Explain the methods to found compound interest

Answer 1

the methods to find Compound Interest are :

1.first apply the formula given below:
amount=principal×(1+rate/100)^time
and then add the amount and the principal which will be the compound interest
2.another method to find the Compound Interest directly is by appling the formula given below:
COMPOUND INTEREST=P [ ( 1 + R/100 ) T - 1]

Answer 2

Compound interest is calculated by multiplying the initial principal amount by one plus the annual interest rate raised to the number of compound periods minus one.

According to formula,

to formula,An = P( 1 +r/100)

to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initially

to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)

to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"

to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)

to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)

to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2

to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)

to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)you can see that A2/A1 = A3/A2

to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)you can see that A2/A1 = A3/A2so, {An} is in Geometric progression.

to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)you can see that A2/A1 = A3/A2so, {An} is in Geometric progression.now,

to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)you can see that A2/A1 = A3/A2so, {An} is in Geometric progression.now,amount payable after 5years

to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)you can see that A2/A1 = A3/A2so, {An} is in Geometric progression.now,amount payable after 5yearsA5 =10,000(1.1)^5

to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)you can see that A2/A1 = A3/A2so, {An} is in Geometric progression.now,amount payable after 5yearsA5 =10,000(1.1)^5=16, 105.1 Rs

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