Question

explain the nature of roots of x^2-4+3=0​

Answer 1

Solution==>>

x²-4+3=0

x²=4-3

x²=1

x=±√1

x=±1

x=+1,-1

Answer....

Answer 2

the formula is
b^2 - 4ac
-4)^2 -4(1)(3)
16-12
=4
real roots as d>0



pls mrk as brainlist