Chemistry, asked by TbiaSupreme, 1 year ago

Explain the preparation and properties of boric acid.

Answers

Answered by swagg0
7
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Preparation:
Boric acid is prepared by reacting minerals such as borax (Na2B4O7·10H2O), with strong acids like HCl:

Na2B4O7·10H2O + 2 HCl → 4 H3BO3 + 2 NaCl + 5 H2O
It can also be prepared by the hydrolysis of boron trihalides (such as BBr3) or diborane (B2H6):

BBr3 + 3 H2O → B(OH)3 + 3 HBr

B2H6 + 6 H2O → 2 B(OH)3 + 6 H2
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Physical properties:

Boric acid is a white crystalline solid with a density of 1.435 g/mL, melting point of 170.9 °C and boiling point of 300 °C.

Chemical properties:
Boric acid is a weak monobasic acid, and is considered a Lewis acid. It dissolves in boiling water and in anhydrous sulfuric acid. When heated to high temperatures (over 170 °C), it undergoes dehydration to form metaboric acid (HBO2):
H3BO3 → HBO2 + H2O.

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