Chemistry, asked by nayyu469, 5 months ago

Explain the preparation of sodium zincate.

Answers

Answered by manshi8723
4

Answer:

Solutions of sodium zincate may be prepared by dissolving zinc, zinc hydroxide, or zinc oxide in an aqueous solution of sodium hydroxide. ... Zn + 2 H2O + 2 NaOH → Na2Zn(OH)4 + H. From such solutions, one can crystallize salts of containing the anions Zn(OH)42−, Zn2(OH)62−, and Zn(OH)64−.

Chemical formula: Na2Zn(OH)4

Molar mass: 179.418 g/mol

Explanation:

HOPE IT HELP YOU

Answered by REDPLANET
2

Answer:

Solutions of sodium zincate may be prepared by dissolving zinc, zinc hydroxide, or zinc oxide in an aqueous solution of sodium hydroxide.

Zn + 2 H2O + 2 NaOH → Na2Zn(OH)4 + H2

From such solutions, one can crystallize salts of containing the anions Zn(OH)42−, Zn2(OH)62−, and Zn(OH)64−.

Similar questions