Question

explain the principle of a capacitor. derive an expression for the capacitance of a parallel plate capacitor.

Answer 1

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Answer 2

Answer:

Explanation:

Consider an uncharged metallic plate at a distance d from charged plate which becomes negatively charge.

The electric field near the surface of charged conductor is

E= SIGMA÷E0

BUT sigma = g÷a

E = q÷ Ae0

Wkt relation b/w e and v E = v/d

So v = q/ae0 d

Capacitance is given by

C= q/qd/Ae0

C= A e0/d

If dirlectic medium us placed i b/w then,

C = A e0 er/ d