Math, asked by nainakalki31, 9 months ago

Explain the procedure for this sum...

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Answered by divijahari
0

Step-by-step explanation:

first multiply the values of the first term with values of the second term:

3x²(x²-x-1) -x(x²-x-1) +5(x²-x-1)

then, let's multiply them

3x²*x²=3x⁴

3x²*-x=-3x³

3x²*-1=-3x²

the first term is simplified as 3x⁴-3x³-3x²

next -x*x²=-x³

-x*-x=x²

-x*-1=x

the second term is simplified as -x³+x²+x

next 5*x²=5x²

5*-x=-5x

5*-1=-5

the third term is simplified as 5x²-5x-5

now let's simplify everything

3x⁴-3x³-3x²-x³+x²+x+5x²-5x-5

now add all the like terms first let us group it

3x⁴+(-3x³-x³) +(-3x²+x²+5x²) +(x-5x) -5

after simplification we get

3x⁴-4x³+3x²-4x-5

hope it helps you

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