Question

Explain the process clearly and detailed.​

Answer 1

Answer:

The Process and the heat transfer at each step is as follows-

●From 12g of ice at -10°C to 12g of ice at 0°C = m×s×dT = 12g × 0.5Cal/g°C × (0-(-10°C)) = 60Cal

{Specific heat of ice 0.5Cal/g°C}

●From 12g of ice at 0°C to 12g of water at 0°C = m×Lf 12g× 80Cal/g = 960Cal

{Heat capacity of fusion 80Cal/g}

●From 12g of water at 0°C to 100°C = m×s×dT = 12g × 1Cal/g°C × (100-0)°C = 1200Cal

{Specific heat of water is 1Cal/g°C}

●From 12g of water at 100°C to 12g of water vapour at 100°C = m× Lv = 12g× 540Cal/g = 6480Cal

{Heat capacity of vaporization 540Cal/g}

●Total = 60+960+1200+6480 = 8700Cal

hope this will help you