Explain the process of early cleavage till the formation morula.
Answers
Answered by
3
Cleavage occurs during its passage through the Fallopian tube to the uterus. In humans, cleavage is complete or holoblastic and equal.
which is the process by which the zygote rapidly divides without growing to become multicellular. Cleavage uses the process of mitosis to replicate the genome and then divide the cells in half; however, unlike normal mitosis, there is no growth phase between divisions during cleavage.
The first division occurs about a day after fertilization, and subsequent divisions occur every 12 to 24 hours after that. The zygote divides several times to form a mass of cells called a morula, which is an embryonic stage consisting of a solid, compact mass of 16 or more cells. The morula is the first embryonic stage where mammalian cells can be categorized as being either internal or external. The cells continue to divide, and when the mammalian morula reaches the 64 cell stage, the internal and external cells become separate lineages.
HOPE IT HELPS YOU✌✌
PLEASE MARK BRAINLIEST ANSWER ❤❤
which is the process by which the zygote rapidly divides without growing to become multicellular. Cleavage uses the process of mitosis to replicate the genome and then divide the cells in half; however, unlike normal mitosis, there is no growth phase between divisions during cleavage.
The first division occurs about a day after fertilization, and subsequent divisions occur every 12 to 24 hours after that. The zygote divides several times to form a mass of cells called a morula, which is an embryonic stage consisting of a solid, compact mass of 16 or more cells. The morula is the first embryonic stage where mammalian cells can be categorized as being either internal or external. The cells continue to divide, and when the mammalian morula reaches the 64 cell stage, the internal and external cells become separate lineages.
HOPE IT HELPS YOU✌✌
PLEASE MARK BRAINLIEST ANSWER ❤❤
Similar questions