Question

explain the process of heating ferrous sulphate (decomposition of ferrous sulphate crystals )​

Answer 1

Answer:

• Ferrous sulphate crystals(FeSO₄) are green in colour. When these crystals are heated they lose their water of crystallisation molecules and become anhydrous ferrous sulphate and their colour becomes white.

• On further heating, these white coloured anhydrous ferrous sulphate decomposes into ferric oxide(Fe₂O₃), sulphur dioxide(SO₂) & sulphur trioxide(SO₃). This reaction is called decomposition reaction.

• Hence, ferrous sulphate crystals finally became three simpler products upon decomposition - ferric oxide, sulphur dioxide & sulphur trioxide. Ferric oxide obtained here is reddish-brown in colour while the other two are gases. These gases are colourless and are poisonous too.

Reaction for the decomposition process:-

• $\rm{2FeSO_4(s)\xrightarrow{\text{Heat}}Fe_2O_3(s)+SO_2(g)+SO_3(g)}$

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Additional Information:

Decomposition reaction:-

• A type of chemical reaction in which a single reactant splits/broke down into a number of simpler products is called a decongestant reaction. All decomposition reactions are endothermic and require energy in the form of heat, light or electricity to occur.

Answer 2

2FeSO₄(s) $→$ Fe₂O₃(s) + SO₂(g) +SO₃(g)

• FeSO₄ = Ferrous(Iron-II) sulphate (pale green).
• Fe₂O₃ = Ferric (Iron-III) oxide (white).
• SO₂ = Sulphur dixide gas.
• SO₃ = Sulphur trioxide gas.

When Pale green colour of Ferrous(Iron-II) Sulphate crystals (hydrated) are heated,

they loose their water of crystallization and results in the formation of anhydrous Ferric (Iron-III) Oxide which is white in colour.

Two gases are evolved which are Sulphur dixide gas and Sulphur trioxide gas.

This is an example of decomposition

reaction.