Explain the Rault's law of partial pressure.
Answers
Answer:
Raoult’s law has been named after François-Marie Raoult, a French chemist who while conducting an experiment found out that when substances were mixed in a solution, the vapour pressure of the solution decreased simultaneously. Raoult’s law was established in the year 1887 and is also considered as the law of thermodynamics.
We will further take an in-depth look at Raoult’s law and understand the principle behind the law as well as its application and limitations in this lesson.
What is Raoult’s Law?
Raoult’s law states that a solvent’s partial vapour pressure in a solution (or mixture) is equal or identical to the vapour pressure of the pure solvent multiplied by its mole fraction in the solution.
Mathematically, Raoult’s law equation is written as;
Psolution = ΧsolventP0solvent
Where,
Psolution = vapour pressure of the solution
Χsolvent = mole fraction of the solvent
P0solvent = vapour pressure of the pure solvent
We will further understand the principle behind the law by looking at the example below.
Consider a solution of volatile liquids A and B in a container. Because A and B are both volatile, there would be both particles of A and B in the vapour phase.
Hence, the vapour particles of both A and B exert partial pressure which contributes to the total pressure above the solution.
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Established by French chemist François-Marie Raoult in 1887, it states that the partial pressure of each component of an ideal mixture of liquids is equal to the vapor pressure of the pure component multiplied by its mole fraction in the mixture. .
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