explain the reaction of metal zinc with the sulpuric acid with the help of suitable activity mention producer ,observationand conculsion
Answers
Reaction of zinc with acids
Zinc metal dissolves slowly in dilute sulfuric acid to form solutions containing the aquated Zn(II) ion together with hydrogen gas, H2. In practice, the Zn(II) is present as the complex ion [Zn(OH2)6]2+.
Answer: Hey! Hope this helps you.
Even dilute sulfuric acid reacts with many metals via a single displacement reaction as with other typical acids, producing hydrogen gas and salts (the metal sulfate). It attacks reactive metals (metals at positions above copper in the reactivity series) such as iron, aluminium, zinc, manganese, magnesium, and nickel.
Cu is not used in displacement reaction as it is present below hydrogen in activity series so cannot displace hydrogen from sulfuric acid.
Procedure
Take a clean and dry test tube.
Add zinc granules in it.
Submerge the zinc granules in the test tube by adding hydrochloric acid to it.
Close the mouth of the test tube with cork which has a glass delivery.
A robust explosion takes place between 2-3 minutes liberating colourless and odourless gas.
When a burning match stick in got near the glass tube mouth the gas burns with a pale blue flame with a pop sound.
Reaction:
2HCl(aq) + Zn(s) → ZnCl2(aq) + H2↑
Explanation:
