Question

Explain the reaction of sodium carbonate with hydrochloric acid by drawing the diagram ?​

Answer 1

Answer:

When dilute hydrochloric acid reacts with sodium carbonate, then sodium chloride, carbon dioxide and water are formed. A brisk effervescence is seen in the release of carbon dioxide.

NaHCO3(s) + 2 HCl → 2NaCl(aq) + CO2(g) + H2O(l)

Answer 2

The product that is formed when sodium carbonate and hydrochloric acid is sodium chloride.

 

• When sodium carbonate is treated with hydrochloric acid, there are three products that are formed and they are sodium chloride, carbon dioxide, and water.

• The reaction involves: Na₂CO₃ + 2HCl → NaCl + CO₂ + H₂O

• The reaction is associated with the presence of brisk effervescence indicating the formation and liberation of CO₂ gas.

• The states of each of the molecules are: sodium carbonate appears as solid,  sodium chloride is in aqueous, carbon dioxide is in gaseous form, and water is in the liquid state.