explain the reason for your answer
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Given, x = 2^1/3 - 2^-1/3
2x^3 = 2(2^1/3 - 2^-1/3)^3
= 2((2^1/3)^3 - 2^(-1/3)^3 - 3(2^1/3)^2(2^-1/3) + 3(2^1/3)(2^-1/3)^2)
= 2(2 - 2^-1 -3(2^2.3 - 1/3) + 3(2^1/3-2/3)
= 2(2 - 1/2 -3(2^1/3 - 2^-1/3))
= 4 - 1 - 6(2^1/3 - 2^-1/3)
= 3 - 6x
2x^3 = 3 - 6x
2x^3 + 6x = 3.
Hope this helps!
2x^3 = 2(2^1/3 - 2^-1/3)^3
= 2((2^1/3)^3 - 2^(-1/3)^3 - 3(2^1/3)^2(2^-1/3) + 3(2^1/3)(2^-1/3)^2)
= 2(2 - 2^-1 -3(2^2.3 - 1/3) + 3(2^1/3-2/3)
= 2(2 - 1/2 -3(2^1/3 - 2^-1/3))
= 4 - 1 - 6(2^1/3 - 2^-1/3)
= 3 - 6x
2x^3 = 3 - 6x
2x^3 + 6x = 3.
Hope this helps!
sanidhyasingla:
i don't understand third step from the top
i think you have use the identity wrong
(a+b)3=a3+b3+3ab (a+b)
sorry
That is (a-b)^3 formula.
(a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3
(a-b)3 = a3-b3-3ab(a-b)
yes.
U have written (a-b)3 = a3-b3-3ab(a-b) = a^3- b^3 - 3a^2b + 3ab^2
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sorry bro I could do this last night because here light was not there
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