Math, asked by sanidhyasingla, 1 year ago

explain the reason for your answer

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Answered by siddhartharao77

Given, x = 2^1/3 - 2^-1/3

2x^3 = 2(2^1/3 - 2^-1/3)^3

= 2((2^1/3)^3 - 2^(-1/3)^3 - 3(2^1/3)^2(2^-1/3) + 3(2^1/3)(2^-1/3)^2)

= 2(2 - 2^-1 -3(2^2.3 - 1/3) + 3(2^1/3-2/3)

= 2(2 - 1/2 -3(2^1/3 - 2^-1/3))

= 4 - 1 - 6(2^1/3 - 2^-1/3)

= 3 - 6x

2x^3 = 3 - 6x

2x^3 + 6x = 3.

Hope this helps!

sanidhyasingla: i don't understand third step from the top

sanidhyasingla: i think you have use the identity wrong

sanidhyasingla: (a+b)3=a3+b3+3ab (a+b)

sanidhyasingla: sorry

siddhartharao77: That is (a-b)^3 formula.

siddhartharao77: (a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3

sanidhyasingla: (a-b)3 = a3-b3-3ab(a-b)

siddhartharao77: yes.

siddhartharao77: U have written (a-b)3 = a3-b3-3ab(a-b) = a^3- b^3 - 3a^2b + 3ab^2

Answered by Anonymous

sorry bro I could do this last night because here light was not there

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