Question

explain the shape and bond angle of NH3 H2O on the basis of hybridization

Answer 1

$Here \: is \: the \: answer \: of \: your \: question$


`$\textbf{Hyberdisation}$`

Hyberdisation can be defined as the intermixing of orbitals of slightly different energies. So, as to re-distribute their energies resulting in the formation of new orbitals of equal energy and identical shape. The new orbitals thus formed are called Hybrid orbitals.

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`$\textbf{Shape and bond angle of NH3}$`

→ Shape = Trigonal pyramidal.

→ Bond angle = 107°

→ Valence electrons of N = 5

Atoms of H = 3

Formula = ½ (V - L - S)

= ½ (5 + 3)

= 8/2

= 4

Hyberdisation of NH3 = Sp³

→ [Diagram is in Attachment]

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`$\textbf{Shape and bond angle of H2O}$`

→ Shape = V or bent shape

→ Angle = 104.5°

→ Valence electrons of O = 6

Atoms of H = 2

Formula = ½ (V - L - S)

= ½ (6 + 2)

= 8/2

= 4

→ Hyberdisation of H2O = Sp³

→ [Diagram is in Attachment]

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Answer 2

Angle of NH3 = 1o7°from 109.5°

And H2O = 104°from109.5° are reduced