Question

explain the structure of sf4 and sf6​

Answer 1

Answer:

SF4 has four bonded atoms and one lone pair. The five electron pairs around sulphur adopt trigonal bipyramidal geometry in which one position is occupied by a lone pair. ... SF6 Sulfur Hexafluoride. Sulfur hexafluoride has 12 electrons around the central sulfur atom.

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Answer 2

SF4 has the structure of a see-saw and SF6 has the structure of an octahedral.

Structure of SF4:

• It has 5 areas of electron density.
• It has. a bond angle of 102° between Sulphur and the equatorial fluorine atoms.
• It has a bond angle of 173° between the Sulphur and axial fluorine atoms.
• The hybridization is sp³d.
• It has 2 bond pairs and one lone pair.
• The oxidation state of Sulphur in this molecule is +4.
• These are arranged in a trigonal bipyramidal shape.

Structure of SF6:

• In an SF6 molecule, the central atom 'S' undergoes sp³d² hybridization.
• The 2 nd excited state electronic configuration of S-atom is

$1s^ 2 2s^ 2 2p^ 6 3s^ 1 3p x ^ 1 3p y ^ 1 3p z ^ 1 3d x^ 2 -y^ 2 3d z^ 2.$

The electronic configuration of Fluorine is

$1s ^ 2 * 2s ^ 2 * 2p_{x} ^ 2 * 2p_{y} ^ 2 * 2p_{z} ^ 1$

• Sulfur atoms can form six half-filled sp³d² hybrid orbitals.
• Each sp³d² hybrid orbitals of S-atom axially overlap with overline 2Pz orbitals of F-atom to form six sigma sp³d² bonds
• It results in the formation of the SF6 molecule.
• The shape of this molecule is octahedral and the bond angle is 90 degrees.

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