Question

explain the structure of XeF4 on the basis of vsepr theory​

Answer 1

Answer:

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Explanation:

THE STRUCTURE OF XEF4 ON THE BASIS OF VSEPR THEORY IS AS FOLLOWS:

XeF4 has a square planar structure because;

The central atom Xe have hybridisation as sp3d2 so it should be octahedral but let us put the rules of VSEPR theory that there should be minimum repulsive force between the bond paired and lone pair electrons.

We know that there is minimum repulsion when the compound is in trans state and the other element while taking equatorial place.

So putting the fluorine at the opposite side we get the compound in trans or we can say that there is minimum repulsive force between the bond paired and lone pair of electrons.

Thus we come to an end that due to all this phenomena the shape of compound XeF4 is Square planar.