Explain:the total mechanical energy of a free falling object always remains contact
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CONSIDER AN OBJECT OF MASS "m" situated at position "a" at a height "h" from ground.
at position "a"
PE=mgh
ke=0
te=ke+pe
te=0+mgh=mgh
at point b
pe=0
ke=1/2mv2
but v2=u2+2as
u=0
a=g
s=h
v2=0+2gh
1/2m multiplied by 2gh=mgh
2&2 cancel
te=pe+ke
0+mgh=mgh
hence proved
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