Explain the value of sinx when limit tends to infinity
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we know that sin(x) value belongs to [-1,1]
even when x tends to infinity the value of sin(x) lies between -1 and 1. Which is defined value
when x tends to infinity 1/x will tend to 0.
so, when x tends to infinity sin(x)*(1/x) will be [ (some finite value lying between -1 and 1)*(0)]
=> sin(x)/x=0, when x tends to infinity
I HOPE IT IS HELPFUL TO YOU
we know that sin(x) value belongs to [-1,1]
even when x tends to infinity the value of sin(x) lies between -1 and 1. Which is defined value
when x tends to infinity 1/x will tend to 0.
so, when x tends to infinity sin(x)*(1/x) will be [ (some finite value lying between -1 and 1)*(0)]
=> sin(x)/x=0, when x tends to infinity
I HOPE IT IS HELPFUL TO YOU
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