explain the variation of temperature according to prevost theory of heat exchange?
Answers
Answer:
Prevost's Theory of Heat Exchanges
A body at a higher temperature than the surroundings radiates heat at a faster rate than it absorbs. ∴ It loses heat and its temperature falls. A body which is at a lower temperature than the surroundings absorbs heat at a faster rate than it radiates. ∴ It gains heat.
Answer:
Explanation:
In 1792, Pierre Prevost put forward a theory of exchange of heat. According to this theory, all bodies at all temperatures above the absolute zero temperature (0 K) radiate thermal energy to the surroundings and at the same time receive radiant energy from the surroundings. Thus, there is continuous exchange of radiant energy between a body and its surroundings. The quantity of radiant enersy (thermal energy)
emitted bya body per unit time depends upon the nature of the emitting surface, the area of the surface and the temperature of he surface. The quantity of radiant energy absorbed by a body per unit time depends upon the nature of the absorbing surface, the area of the surface and the time rate at which the radiant energy is incident on the body. If the time rate of emission of thermal energy is greater than the time rate ot absorption of thermal energy, the temperature of the body falls. If the emission rate is less than the absorption rate, the temperature of the body increases. If the emission rate equals the absorption rate, the temperature of the boay remains constant.
[Note : A body appears red if its temperature is around 800,and white hot if its temperature 1s around 3000 C]