Question

explain the work done when a force acts on a body at an angle with the direction of motion

Answer 1

this may help u........

Answer 2

Explain the work done when a force acts on a body at an angle with the direction of motion ...

$\huge\underline{\underline{\red{\textbf{Explanation : -}}}}$

When an force is applied in pulling body at angle θ . which is horizontal then the work done is equal to the product of horizontal component of the force and distance moved by the body.

$\sf \: w = f \: cos \: \theta \times s \\ \sf \: w = f.s \: cos \theta \\ \sf \bullet \: when \: \theta = 90 {}^{ \circ} \\ \sf \: w = f \times s \times cos \: 90 \degree \\ \sf \: w = f \times s \times 0 \\ \boxed{ \bf \: w = 0}$

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