Question

Explain the working of p-n junction diode as a full wave rectifier. Draw the circuit diagram of full wave rectifier.

Or

Draw a circuit diagram of full wave rectifier for p-n junction diode and explain its working method. Show the waveforms of input and output voltages. ​

Answer 1

Answer:

When the diode rectifies the whole of the AC wave, it is called full wave rectifier. ... Therefore, the diode D1 is forward biased and D2 is reverse biased. The flow of current in the load resistance RL is from A to B. During the negative half of the input signal, S1 and S2 are negative and positive respectively.

Answer 2

P-N Junction as full wave rectifier

Definition of rectifier

Rectifier is a circuit which convert ac to unidirectional pulsating output . in other words its convert ac to dc

Full Wave rectifier

It rectifies both halves of ac input signal

i)During Positive half-circle

Diode

$\sf D_1\longrightarrow Forward\:biased\\\sf D_2\longrightarrow Reverse\:biased$

$\sf Outpu t \: Signal\longrightarrow obtained\:due\:to\:D-_1 \:only$

ii) During negative half cycle

Diode

$\sf D_1\longrightarrow Reverse\:biased\\\sf D_2\longrightarrow Forward\:biased$

$\sf Outpu t \: Signal\longrightarrow obtained\:due\:to\:D-_2 \:only$

iii) Fluctuating $\sf dc \longrightarrow \boxed{\sf filter}\longrightarrow Constant\:dc$

iv) Output voltage is obtained across the load resistance Rₗ . it is not constant but pulsating in nature

v) Average Output

$\sf V_{av}=\dfrac{2V_o}{\pi },I_{av}=\dfrac{2I_o}{\pi}$

vi) R.m.s. Output

$\sf V_{rms}=\dfrac{V_o}{\sqrt{2}},I_{rms}=\dfrac{I_o}{\sqrt{2}}$

vii) ripple Factor ; r = 0.48=48%

viii) ripple Frequency; The ripple Frequency of full wave rectifier = 2×(frequency of input ac)

ix) peak inverse voltage(PIV) : it's value is 2V₀

x) Efficiency

$\sf n_\% = \dfrac{81.2}{1+\dfrac{r_1}{R_1} }$

For $\sf r_1\ll R_L$