Question

Explain this please ^_^​

Answer 1

Answer:

See below.

Explanation:

Mass of 200 bullets where the mass of each bullet is 0.03 kg,

$M = 200 \times 0.03 = 6 \ kg$

Change in momentum,

$\Delta p = M( 50 ) - [ M( -30) ] = 80M$

As 200 bullets are hitting the plate in a second, the change in momentum occurs in 1 second too.

$\Delta t = 1 \ s$

The average force is given by,

$F_{avg} = \frac{\Delta p}{\Delta t}$

Substituting the respective values,

$F_{avg} = \frac{80M}{1} \ N = 80 \times 6 \ N = 480 \ N$

Pro Tip:

Whenever average values are asked ( like avg velocity, acceleration, force etc. ), just calculate the final and initial values and divide them by the time in which they occurred.

Answer 2

Answer:

Average force on the plate is change in momentum per unit time.

F=

t

nmv

=

1

200×0.03×30

=180N.

plzzz mark it as brainliest.....