Explain this please.
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Side of the square = 10 m
Perimeter of the square = 4X 10 = 40 m
He completes 1 round in 40 s.
So, speed = 40/40 = 1 m/s
distance covered in 2 min 20 s or 140 s is = 140 X 1 = 140 m
Number of rounds of the square completed in moving through 140 m is = 140/40 = 3.5
In 3 rounds the displacement is zero. In 0.5 round the farmer reaches the diagonally opposite end of the square from his starting point.
That means if the farmer starts from point A of the square field, he reaches point C.
Therefore, displacement is AC.
Assume ABC is a right angled triangle.
Therefore,
AC2= AB2 +BC2
AC2= (10)2 +(10)2
AC2= 100+100
AC2=200
AC = (200)1/2
AC= 10× (2) ½
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