explain this please.in 9th cbse
Attachments:

Answers
Answered by
2
OA=OB
Because as we know tangent is a straight line they r radius from there.
AM=BM as they r divided by a mid point.
the third answer is by SSS postulate
the fourth answer is as AB is a straight line and M is a mid point therefore they r 90°.
hope this helps...
pls mark it as the brainliest...
Because as we know tangent is a straight line they r radius from there.
AM=BM as they r divided by a mid point.
the third answer is by SSS postulate
the fourth answer is as AB is a straight line and M is a mid point therefore they r 90°.
hope this helps...
pls mark it as the brainliest...
Answered by
1
IN TRIANGLE OAM AND OBM,
OM=OM (COMMON)
ANGLE AMO=ANGLE BMO (BECAUSE ANGLE A=ANGLE B AS WELL AS ANGLE AOM=ANGLE BOM AS IT IS A RULE THAT IF 2 SIDE OF TRIANGLE ARE EQUAL THEN ANGLES ARE ALSO EQUAL.)
AM=BM (AS M IS CENTRE POINT OF AB)
SO TRIANGLE OAM AND OBM ARE EQUAL BY SAS.
AM=BM (BY CPCT)
OM=OM (COMMON)
ANGLE AMO=ANGLE BMO (BECAUSE ANGLE A=ANGLE B AS WELL AS ANGLE AOM=ANGLE BOM AS IT IS A RULE THAT IF 2 SIDE OF TRIANGLE ARE EQUAL THEN ANGLES ARE ALSO EQUAL.)
AM=BM (AS M IS CENTRE POINT OF AB)
SO TRIANGLE OAM AND OBM ARE EQUAL BY SAS.
AM=BM (BY CPCT)
Similar questions
Social Sciences,
10 months ago
Math,
10 months ago
Computer Science,
10 months ago
History,
1 year ago
Science,
1 year ago
English,
1 year ago
Geography,
1 year ago