Question

explain this plz ➡️➡️➡️➡️➡️➡️✌​

Answer 1

$<p>I <span style="font-size:500%;color:red;">&smile;</span> </p></p><p>$

$\huge \red { \bigstar{ \underline{ÀNSWER}}}$

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the average distance of the earth from the sun

$r = 1au = 1.496 \times {10}^{11} m$

$i) \: as \: 1 \: light \: year = 9.46 \times {10}^{15} m$

so,

$r = \frac{1.496 \times {10}^{11} }{9.46 \times {10}^{15} } ly$

$= 1.58 \times {10}^{ - 15} ly$

$ii) \: as \: 1 \: parsec = 3.08 \times {10}^{16} m$

$r = \frac{1.496 \times {10}^{11} }{3.08 \times {10}^{16} }$

parsec=

$4.86 \times {10}^{ - 6}$

parsec

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Answer 2

Answer:

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