Question

explain this question.......​

Answer 1

no of moles of CH4 mole atoms =0.5×5=2.5

no of atoms =2.5×NA

THEREFORE CH4 HAS MAXIMUM NO OF ATOMS

SEE THE AATACHMENT YOUR ANSWER IS THIS AND I THINK IT IS CORRECT

#TOGETHER WE GO FAR✔✔

Answer 2

$\mathfrak{\huge{\blue{\underline{\underline{AnswEr :}}}}}$

1] 11.2 litre of SO2 at NTP

No. of SO2 Mole = Volume/Vm = 11.2/22.4 = 1/2

No. of Atom = 1/2 × 3 × Na = 1.5Na

2] 22.4 litre of Helium at NTP

No. of Helium Mole = 22.4/22.4 = 1

No. of Atom = 1 × 1 × Na = 1Na

3] 2gm of Hydrogen

No. of Hydrogen Mole = 2/2 = 1

No. of Atom = 1 × 1 × Na = 1Na

4] 11.2 litre of Methane at NTP

No. of Methane Mole = 11.2/22.4 = 1/2

No. of Atom = 1 × 1/2 × Na = 0.5Na