Question

EXPLAIN THIS QUESTION FIRST AND I WILL MARK YOU AS THE BRAINLIEST
The ratio of electric field intensity at distance 5 cm to that at 10 cm from a point charge 5Q in air is
A) 2 : 1 B) 1 : 2 C) 1 : 4 D) 4 : 1

Answer 1

Answer:

Explanation:

THE GIVEN CHARGE =5 Q

DISTANCE, R1= 5 CM= 0.05 M

DISTANCE,R2= 10 CM=0.10 M

ELECTRIC FIELD INTENSITY,E=F/Q

ELECTIC FORCE=(1/4*PI E0) Q/R²

E1/E2=F1*Q/F2*Q

E1/E2=F1/F2

BUT F INVERSELY PROPORTIONAL TO R²

E1/E2=R2²/R1²

E1/E2=10*10/5*5

E1/E2=4:1.

HOPE IT HELPS.

Answer 2

option d is correct 4:1