Explain three different ways in which children often regroup the two numbers while undertaking operations on them, using the example of 57 and 38, while solving 57-38.
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This is how children can regroup the numbers while doing 57 - 38
1.
Take away 7
so we have 50 and 31
Then take away 1
so we have 49 and 30
Then take away 30 from 49
So we have the answer 19
2.
Regroup the two numbers in their ones and tens
So for 57, we have 5 tens and 7 ones
and for 38, we have 3 tens and 8 ones
Then, we realize we don't have enough ones for minus.
so we "borrow" a ten from the 5 tens and 57 becomes 4 tens and 17 ones
we can take 8 away from 17 and that leaves us 9
after we deal with ones, we can take care of the tens... take away 3 tens from 4 tens and leave us 1 ten.
so the answer is 1 ten and 9 ones which is 19.
1.
Take away 7
so we have 50 and 31
Then take away 1
so we have 49 and 30
Then take away 30 from 49
So we have the answer 19
2.
Regroup the two numbers in their ones and tens
So for 57, we have 5 tens and 7 ones
and for 38, we have 3 tens and 8 ones
Then, we realize we don't have enough ones for minus.
so we "borrow" a ten from the 5 tens and 57 becomes 4 tens and 17 ones
we can take 8 away from 17 and that leaves us 9
after we deal with ones, we can take care of the tens... take away 3 tens from 4 tens and leave us 1 ten.
so the answer is 1 ten and 9 ones which is 19.
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