Question

Explain two different ways that you can solve the exponential equation 3^(x+2) = 8​

Answer 1

Answer:

by taking log both sides

log3^(x+2)=log2^3

(x+2)log3=3log2

(x+2)/3=log2/log3

(x+2)/3=log₃²

(x+2)=3×0.75

x=2.25-2

x(approx)=0.25

or,

3ˣ×3²=8

3ˣ=8/9

log3ˣ=log8/9

xlog3=log8/9

x = (log8/9)/log3

x = (0.9-0.95)/0.4

x = -0.05/0.4

x = -0.1