Question

explain uniform circular motion and debuct the expression for motion of satellite​

Answer 1

Answer:

motion of satellite is circular

Answer 2

Uniform circular motion is the motion of an object in a circle at a consistent speed.

• A circular motion is defined as a bodily movement that follows a circular route. The term "uniform circular motion" refers to the movement of objects in a motion of a body traveling along a circular course at a steady pace.
• If a particle is traveling in a circle, it must be experiencing some acceleration in the center's direction causing it to rotate around the center. The motion is circular and constant because the particle's velocity is perpendicular to acceleration in direction, not magnitude. The force operating in the desired direction of the center is termed centripetal force, and the acceleration can be known as centripetal acceleration.
• The acceleration is: ar = v2r = 2r in the case of uniform circular motion.

       If the particle's mass is m, we may deduce from Newton's second    equation of motion that:

                             F = ma

                          mv2r= mω2r

Uniform circular motion is exemplified by the orbiting of man-made satellites orbiting the globe. The earth's gravitational force keeps the satellites circling the globe in a circular orbit

• In the Earth's orbit is round, the period of rotation of satellite its orbital speed is inversely related. A satellite's period is termed as the time taken by it to complete one full orbit around an object or the Earth. The Earth's revolves around the sun lasts one year.The period may be used to determine the speed and radius of the satellite at which it orbits.

• The speed of a satellite orbiting an object is stated as using the equation. : v=Gm2r−−−−−√

      Where v is the satellite's speed.

       The orbit's radius is denoted by r.

       The satellite's circular orbit is determined by:

2πr

Where r stands for radius of the orbit and T stands for the period, the orbital speed must be.

       2πrT. It gives,  Gm2r−−−−−√=2πrT

       After we've solved this for the satellite's time, we'll be able to write    

           v=2πrT

     During the satellite's lifetime 2πrv

In a uniform circular motion, this is the equation for the time of revolution.

Where r is the orbital radius and v is the satellite's speed.