Question

Explain using v.b.t the formation of h2 molecules
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Answer 1

 

Answer

When hydrogen atoms combine to form molecules of hydrogen, 433 KJ/mol energy is released.

 

Whenever atoms combine to form a molecule ,there is always decrease in the energy. Actually, when two H atoms are far separated, they do not have any force of interaction (attractive or repulsive). As they tend to come closer, two different forces operates:

 

(a) The nucleus of one H is attracted towards the electrons of the other H atoms & Vice versa. The energy is released in attraction.

(b) The nuclei of the atoms as well as their electrons repel each other. Energy is needed to overcome the force of repulsion.  

 

 

Now in case, if the magnitude of the attractive  forces is more than that of the repulsive forces, a stable molecule will be formed.

 

However, if the repulsive forces are more than the attractive forces , then the atoms will not combine.

 

If for example HA & HB are two hydrogen atoms & eA & eB are their respective electrons, then attractive & repulsive forces may be shown as follows:

 

                                                        ------------ old attractive forces

                                          _________ new attractive forces

The number of new attractive & repulsive forces is same, but the magnitude of attractive forces is more. Thus, when two hydrogen atoms approach each other, the overall potential energy decreases & hence a stable hydrogen molecule is formed.

Explanation:

Answer 2

Answer:

Formation of h2 molecule

Explanation: