Explain Value Of Sec(-75°) = ?
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Hey dear here is ur answer ******
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sec(-75°)
=sec75°
=sec(45°+30°)
=1/cos(45°+30°)
=1/(cos45°×cos30°-sin45°×sin30°)
=1/(1/√2×√3/2-1/√2×1/2)
=1/(√3-2)/2√2
=2√2/√3-2
=2√2(√3+2)/(√3-2)(√3+2)
=-(2√6+2√4) [Ans.]
Hope it will help u@@@@@@@
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sec(-75°)
=sec75°
=sec(45°+30°)
=1/cos(45°+30°)
=1/(cos45°×cos30°-sin45°×sin30°)
=1/(1/√2×√3/2-1/√2×1/2)
=1/(√3-2)/2√2
=2√2/√3-2
=2√2(√3+2)/(√3-2)(√3+2)
=-(2√6+2√4) [Ans.]
Hope it will help u@@@@@@@
soh2:
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