Question

Explain velocity of a bike is 10m/s, during acceleration is 5m/s2, time required for it is 8 seconds calculate final velocity.​

Answer 1

Explanation:

Given that

The initial speed of car=u= 5 m/s

Acceleration =a=0.2m/s2

Time=t=10s

We need to calculate the distance

We know that

v = u + at

= 5 + 0.2×10

= 5+2

= 7 m/s

s = ut + 1/2at²

= (5×10) + (1/2)×(2/10)×(10×10)

= 50 + 10

= 60 m

Final speed = 7 m/s

Distance traveled in 10 seconds = 60 m

Answer 2

Answer:

$given \: that$

$initial \: velocity \: of \: bike = 10m \: per \: sec {}^{}$

$acceleration \: of \: bike \: = 5m \: per \: s {}^{2}$

$time = 8sec$

$we \: know \: the \: formula$

$acceleration =(initial \: velocity - final \: velocity) \div time$

$a = (v - u) \div t$

$a \times t = v - u$

$5 \times 8 = v - 10$

$40 = v - 10$

$v = 50 \: m \: per \: sec$

$i \: hope \: this \: answer \: may \: help \: you \: dear$