Explain vertical circular motion for three different positions
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Answer:Let a particle make an angle £ with the downward vertical while executing a vertical circle. Then its equation of motion is: T- mgcos£= mv^2/r, T= tension in the string, m= mass of the particle, v= speed, r= radius of the circle. Assuming that the bottom point of the circle is the zero plane of P.E., applying conservation of mechanical energy mv^2/2+mgr(1-cos£)= 0.5*m(v_b)^2 From this equation v^2= (v_b)^2–2gr(1-cos£). Using this equation one can find the velocity of a particle executing vertical circular motion.
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