Physics, asked by cyrusop40, 28 days ago

explain voltage divider biasing in mosfet?​

Answers

Answered by ashayjain
1

Answer:

: Voltage Divider Bias. Voltage divider bias is reminiscent of the divider circuit used with BJTs. Indeed, the N-channel E-MOSFET requires that its gate be higher than its source, just as the NPN BJT requires a base voltage higher than its emitter.

Another configuration that can provide high bias stability is voltage divider bias. Instead of using a negative supply off of the emitter resistor, like two-supply emitter bias, this configuration returns the emitter resistor to ground and raises the base voltage. ... 1: Voltage divider bias.

Answered by ushahira9867
2

Answer:

Voltage divider bias is reminiscent of the divider circuit used with BJTs. ... In general, the layout it is the same as the voltage divider bias used with the DE-MOSFET. The resistors R1 and R2 set up the divider to establish the gate voltage. As the source terminal is tied directly to ground, this means that VGS=VG.

Explanation:

Another configuration that can provide high bias stability is voltage divider bias. Instead of using a negative supply off of the emitter resistor, like two-supply emitter bias, this configuration returns the emitter resistor to ground and raises the base voltage.

Hope it's helpful

Similar questions