Question

explain what is the effect of inserting a dielectric slab of dielectric constant K between the plates of a charged parallel plate capacitor on the electric field and the capacitance of the capacitor plZ help​

Answer 1

Answer:

When the dielectric is placed between the two plates of parallel plate capacitor, it is polarized by the electric field present. ... When the dielectric is fully placed between the two plates of capacitor then it's dielectric constant increases from it's vacuum value.

Answer 2

Explanation:

Place a dielectric layer between two parallel charged metal plates with an electric field pointing from right to left. (Why not left to right? Well, I read from right to left, so it makes the diagrams easier for me to "read".) The positive nuclei of the dielectric will move with the field to the right and the negative electrons will move against the field to the left. Field lines start on positive charges and end on negative charges, so the electric field within each stressed atom or molecule of the dielectric points from left to right in our diagram — opposite the external field from of the two metal plates. The electric field is a vector quantity and when two vectors point in opposite directions you subtract their magnitudes to get the resultant. The two fields don't quite cancel in a dielectric as they would in a metal, so the overall result is a weaker electric field between the two plates. In the electric there is an induced electric field opposite to the applied field, here comes the Lenz law, which says son kills his own father as the induced electicfield opposes the external field. By applying such thing in formula u will Find that capacitance is very increased between two plates. thank u !