Explain what you would observe when a chlorine solution is added to a solution of potassium fluoride
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Explanation:
When chlorine (Cl
2
) gas is passed through an aqueous solution of potassium iodide (KI), the products formed are solid iodine (I
2
) and potassium chloride (KCl). This is a displacement reaction in which the less reactive iodine in potassium iodide is displaced by the more reactive chlorine. The equation can be written as:
2KI(aq)+Cl
2
(g)→2KCl(aq)+I
2
(s)
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