Chemistry, asked by sameerkashif2007, 4 months ago

Explain what you would observe when a chlorine solution is added to a solution of potassium fluoride​

Answers

Answered by Anonymous
6

Explanation:

When chlorine (Cl

2

) gas is passed through an aqueous solution of potassium iodide (KI), the products formed are solid iodine (I

2

) and potassium chloride (KCl). This is a displacement reaction in which the less reactive iodine in potassium iodide is displaced by the more reactive chlorine. The equation can be written as:

2KI(aq)+Cl

2

(g)→2KCl(aq)+I

2

(s)

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