Explain why 7*11*13*+13 and 7*6*5*4*3*2*1+5 are composite numbers.
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Answered by
41
composite number are the number which have more than two factors and no. it self.
for 7*11*13+13 = 13 [7*11*1+1]
here 13 is other than 1 and the no it self so it is factor
for 7*6*5*4*3*2*1+5 = 5[7*6*1*4*3*2*1+1]
here is 5 so is is other than 1 aand no it self so it is coposite.
for 7*11*13+13 = 13 [7*11*1+1]
here 13 is other than 1 and the no it self so it is factor
for 7*6*5*4*3*2*1+5 = 5[7*6*1*4*3*2*1+1]
here is 5 so is is other than 1 aand no it self so it is coposite.
Nitya8:
ok i understood what u want to explain but please work on your english...........no offence ok! :)
but urs was easy to understand thanq :)
Answered by
44
composite number are the numbers having more than two factors..
1.) 7*11*13+13 = 13 [7*11*1+1]
=13[77+1]
=13*78=13*13*2*3
2)7*6*5*4*3*2*1+5 = 5[7*6*1*4*3*2*1+1]
=5[1008+1]
=5[1009]
=5*1009
since the given numbers have more than two factors,these are composite numbers
1.) 7*11*13+13 = 13 [7*11*1+1]
=13[77+1]
=13*78=13*13*2*3
2)7*6*5*4*3*2*1+5 = 5[7*6*1*4*3*2*1+1]
=5[1008+1]
=5[1009]
=5*1009
since the given numbers have more than two factors,these are composite numbers
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