explain why a ray of light passing through the centre of curvature of a concave mirror gets reflectd along the same path after reflection
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pole...
is the correct answer
when we draw a normal in between the incident ray and the reflected ray, this normal is along the direction of the centre of the circle , it is perpendicular to the tangent drawn on a point on the circle. Now we know that the centre of curvature is the centre of the circle from which we took a part of it called a curved mirror. So when the light ray passes through the centre of curvature, the incident ray and normal make a 0° angle with each other as the normal is in the direction of the centre and the ray is coming through the centre. Now we know that the angle of incidence is equal to the angle of reflection( angles made by the incident or reflected ray with the normal) are equal , that is ∠i = ∠r, since ∠i is zero with the normal therefore ∠r is also zero with the normal, so every ray is in the same path. That is why a ray of light passing through the centre of curvature of a concave mirror gets reflected along the same path.