Explain why an ideal octahedral geometry is not observed in [Ti(H2O) 6]3+
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Explanation:
[Ti(H2O)6]3+ is an octahedral complex, and in it the metal is in +3 oxidation state.
The elctronic configuration of
Ti : [Ar] 3d2 4s2
and (after Ti loses 3 of its loosely bound electrons) Ti (+3) can be either : [Ar] 3d0 4s1
or [Ar] 3d1 4s0
Now, since a hald filled 4s orbital here is more stable than the incompletely filled 3d orbital, the earlier configuration is readily achieved.
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