Question

Explain why an object's velocity time graph can have no change while the same object can have a position time graph with a positive change. Use examples if you need to. (2 sentence minimum)

Answer 1

To explain:

Why an object's velocity time graph can have no change while the same object can have a position time graph with a positive change ?

Detailed Explaination:

• First of all , let's take an example of a bus whose position time graph is having a positive change.

$\boxed{\setlength{\unitlength}{1cm}</p><p>\begin{picture}(6,6)\put(2,2){\vector(1,0){3}}\put(2,2){\vector(0,1){3}}\put(2,2){\line(1,1){2}}\put(1.5,4){x}\put(4,1.5){t}\end{picture}}$

• So, the position time graph is having a positive slope. It's equation will be x = ut

• Now, if we try to plot the velocity time graph, we need to differentiate the 1st function.

$\therefore \: v = \dfrac{dx}{dt}$

$\implies\: v = \dfrac{d(ut)}{dt}$

$\implies\: v =u \times \dfrac{dt}{dt}$

$\implies\: v =u = constant$

• So, the velocity time graph will be as follows:

$\boxed{\setlength{\unitlength}{1cm}</p><p>\begin{picture}(6,6)\put(2,2){\vector(1,0){3}}\put(2,2){\vector(0,1){3}}\put(2,4){\line(1,0){2}}\put(1.5,4){v}\put(4,1.5){t}\end{picture}}$

• So, the graph is linear and parallel to the time axis. Hence the velocity is constant and is not having a change even when the position of the bus is changing.

Answer 2

Answer:

Hi

Explanation:

i am 9 standard student