Explain, why Pt (IV) complexes are generally octahedral while Pt (II) complexes are square planar.
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Explanation:
Oxidation states can be measured with all methods including photo electrons: photoelectron absorption or emission spectrocopy, ESCA etc.
Alternatively, if the compound is soluble, you might check the electrochemistry. Pt(II) complexes should give an oxidation in the range of 0 to +1.5 V, Pt(IV) of course not. Pt(IV) complexes in turn shuould be reduced easily.
Furthermore, you can add MeI and see what happens. In case of Pt(II) you will get an oxidative addition, you will see this from the colour change.
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