Question

explain why sulphuric acid form two series of salt

Answer 1

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Sulphuric acid is a dibasic acid that dissociates in 2 stages.

H2SO4 <=> H+ and (HSO4)- — (Ka1)

HSO4- <=> H+ and (SO4)2- —(Ka2)

Ka2 is slightly lower than Ka1, so under the right conditions, you may get (HSO4)- salts.

An reaction between 1 mole of H2SO4 and 1 mole of NaOH will look like this. Both H2SO4 and NaOH are strong acid and bases respectively, so the reaction will go to completion, not hang around at (HSO4)-, since Ka2 is still quite high.

0.5H2SO4 and NaOH →0.5Na2SO4 and H2O

The excess 0.5 moles of H2SO4 will exist as an equilibrium of (HSO4)- and (SO4)2-.

How can I get more (HSO4)- instead of (SO4)2-? The one solution I can think of is a bit ironic: increase the concentration of (SO4)2-. This will shift the equilibrium to the left for the Ka2 reaction.


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Answer 2

sulphuric acid is a dibasic acid that dissociate in two stages
H2SO4 <=> H+and (HSO4) - -(ka1)
HSO4 - <=> H+ and (SO4)2 --(Ka2)
Ka2 is slightly low than Ka1 so under the right condition you may get (HSO4)-salts
An reaction between 1 mole of NaOH will look like this.Both H2SO4 and NaOH are strong acid and base respectively so the reaction will go to completion not hang around at (HSO4)-,since ka2 is still quite high.





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