Question

Explain;


Why $Cr^{2+}$ is a strong reducing agent ?

Answer 1

Answer:

Explanation:

First we see the electronic configuration of Cr.

Cr:[Ar]3d5 4s1

Now, for the bivalent ion,

Cr2+:[Ar]3d4

It acts as a strong reducing agent,ie, it gets oxidised to d3 configuration from d4.Now,from crystal field theory,we know that d3 configuration is highly stable due to half filled t2g orbitals.

So,it acts as a strong reducing agent so that it gets oxidised to a more stable configuration.

Hope you understood

Answer 2

$\Large{\textsf{\pink{\underline{\underline{ANSWER}}}}}$

★ Cr2+ is strongly reducing in nature. It has a d4configuration.

★While acting as a reducing agent, it gets oxidized to Cr3+ (electronic configuration, d3).

★This d3configuration can be written as t32g configuration, which is a more stable configuration.