Question

explain why the value of g is zero at the centre of curvature of the earth​

Answer 1

Answer:

I hope you meant center of earth.

The value of g is maximum at the surface of the earth , it goes in decreasing as we go down , also it goes on decreasing as we go up.

If we look at the relation of g at a depth d from surface

$g' = g(1-\frac{d}{r} )$ where d is depth measured from surface and r is radius of earth

if we substitute d to be r (meaning depth = radius, i.e, at center/core of earth)  we get the value of g to be 0.

If your answer is WHY does gravity not exist at center : this paragraph has answer :

The gravitational force (responsible for acceleration due to gravity g) is caused by all the mass of the earth, It is not caused by a central core force at the center (in case of magnetism, which originates due to molten metals at the core)

The gravitational pull is caused due to the whole mas , each and every granule of the earth's mass and not just the core

if we go down the earth , the amount of mass (of earth) causing the gravitational pull will decrease (take a moment and imagine, the sentence in bold)

so it makes sense that

we go down the earth = the mass of earth below us decrease = less gravitational pull caused by the mass of the earth .

At the center , the mass of earth as we go down reduces from a planetary scale to a particle scale , so mass decreases , gravitational pull decreases c acceleration due to gravity decreases  

I really hope you understood my intuition and got a clear idea about it

Happy learning !

and please do mark brainliest if you understood the answer well.

Answer 2

Answer:

Yes, the gravitational force at the earth's center is zero. ... And closer you come to the surface of earth, more gravitational force acts on you. This is because of the inverse square law .

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