Question

Explain why there must be 8.64 x 10-3 mol of
hydrogen iodide molecules in the equilibrium mixture if 0.68 x10-3 mol of iodine are present?​

Answer 1

Answer:

The correct option is 1

We have,

4.5 moles each of hydrogen and iodine which is heated in a sealed 10litre vessel.

H

2

(g)+I

2

(g)⇋2HI(g)

Since 1 mole of H

2

and one mole of I

2

combine to give 2 moles

of HI then 3 moles of HI would be formed by ICE table,

K

C

for the reaction at equlibrium is :

=

[H

2

][I

2

]

[HI]

2

=

[3][3]

[3]

2

=1