Question

EXPLAIN WIT SOLLUTIONS I WANT YOUR HELP PLZ HELP ME GUYS
I AM LOSTING IN IT PLZ HELP

Answer 1

Explanation:

average speed = total distance / time

= 180 /60 = 3m/s

average velocity = displacement/ time

= 0

Answer 2

Formula:

》Average speed = $\sf{ \dfrac{total\;distance\;covered}{total\;time\;taken}}$

》Average velocity = $\sf{ \dfrac{total\;displacement \;covered}{total\;time\;taken}}$

☆Given:

• length of swimming pool = 90m

• speed of usha(v) = 180m in one minute

• v = 180/60 = 3m/s.

☆Solution:

See the solution with refer to the above image!

》Moving from A to B and back to B her displacement will be 'zero'.

Displacement = shortest distance between initial and final position.

as she is initial and final at 'A', so the displacement = 0.

》Average velocity = disp/time = 0.

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Distance = total length covered from A to B and again A.

》Average speed = $\bf{ \dfrac{total\;distance\;covered}{total\;time\;taken}}$

》$\ v_{av}$ = $\dfrac{x + x}{t_{1}+t_{2}}$

• $\ v_{av}$ = $\dfrac{2x}{ \dfrac{x}{v}+ \dfrac{x}{v}}$

•$\ v_{av}$ = $\dfrac{2}{ \dfrac{1}{v}+ \dfrac{1}{v}}$

•$\ v_{av}$ = $\dfrac{2}{ \dfrac{2}{v}}$

》Average speed = v = 3m/s.

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