explain with 1 example that frictional force is proportional to the normal force
Answers
Answer:
: Explanation: As you can see in the figure the force with which be gold ingot presses against the ground in this situation is just its normal force is the force pushing the two surfaces together and the stronger the normal force the stronger the force due to friction hope it helped u
Answer:
here it is your answer!
Explanation:
NORMAL REACTION - DEFINITION
"When any two surfaces are in contact, a contact force is exerted between the surfaces. Normal reaction is the component of the contact force normal to the contact surface.
For example, for a block placed on ground, the ground exerts an upward normal reaction force on the block."
ANGLE OF FRICTION - DEFINITION
concept
It is the angle ( α ), measured between the normal force (N) and resultant force (R).
A body rests on a rough horizontal plane. A force is applied to the body directed towards the plane at an angle α with the vertical.
The body can be moved along the plane:
Consider a block placed on a rough horizontal plane. Now, the reaction force
R
is because it is equal and opposite to the
weight
W
. If the force
F
is applied to the block towards the plane at an angle α, the resolved forces will act along vertical and horizontal direction.
The horizontal component of force Fsinα have to overcome the frictional force so that the block just begins to slide. Frictional force is equal to limiting friction F
limiting
, when this condition is satisfied the angle of applied force α will be greater than angle of friction α and block can move along the plane.
tanα=μ
LAWS OF FRICTION AND EXAMPLE - EXAMPLE
concept
Laws of Friction are:
When an object is moving, the friction is proportional and perpendicular to the normal force (N)
Friction is independent of the area of contact as long as there is an area of contact.
The coefficient of static friction is slightly greater than the coefficient of kinetic friction.
Within rather large limits, kinetic friction is independent of velocity.
Friction depends upon the nature of the surfaces in contact.
Example: A body of mass M is placed on a rough inclined plane of inclination θ and coefficient friction μ
k
. A force of (mgsinθ+μ
k
mgcosθ) is applied in the upward direction, the acceleration of the body is:
Equating forces along X and Y axes,
N=mgcosθ
Also,
−mgsinθ−μ
k
mgcosθ−ma+mgsinθ+μ
k
mgcosθ=0
∴ma=0